PROBABILITIES OF GENETIC TRAITS
Exercises Involving Dice
When two dice are thrown, find the probability of rolling:
1. two five's 2. a five then a two
3. a five and a two 4. no fours
5. all even number 6. an odd and an even
7. two sevens 8. two values each less than five
9. two values with a sum of
a) eleven b) ten
Checking for Understanding
Find a baby's probability of inheriting ridged fingernails if the genetic make-up of the parents is as follows:
1. father = Rr, and mother = rr
Solution: Since the mother does not have an "R" allele, the baby can't
inherit "RR", so . The possible inheritance for the baby is "Rr" (mother's first
r), "Rr" (mother's second r), "rr", and "rr" again.
2. father = RR, and mother = Rr
3. father = rr, and mother = RR
4. father = rr, and mother = Rr
0
Genetics Probability Exercises
Given the genetic make-up of the parents, determine the indicated probabilities.
1. If the make-up of the father = EeGg, and the mother = EEGg, then find the probability that the child will be:
a. EEGg b. EEgg c. Eegg
d. EeGG e. EeGg f. EEGG
2. If the make-up of the father = Ttqq, and the mother = TtQQ, then find the probability that the child will be:
a. TtQq b. Ttqq c. ttQq
0
d. TTQq e. have the f. have both dominant Q-trait dominant traits
1
3. If the make-up of the father = RrHh, and the mother = RrHh, then find the probability that the child will be:
a. RRHH b. RRHh c. Rrhh
d. RrHH e. RrHh f. RRhh
g. rrHH h. rrHh i. rrhh
j. have the dominant k. have both traits
R-trait dominant
4. If the make-up of the father = Ddtt, and the mother = DdTt, then find the probability that the child will be:
a. the same as the father b. the same as the mother c. Ddtt
d. all dominant traits e. dominant T-trait and f. all traits
recessive d-trait recessive
5. If the make-up of the father = AaBb, and the mother = AaBb, then find the probability that the child will have:
a. all recessive alleles b. all recessive traits c. AaBb
d. all dominant alleles e. all dominant traits f. Aabb
g. dominant A-trait h. recessive a-trait i. aaBb
j. dominant A-trait & k. recessive a-trait &
recessive b-trait dominant B-trait
6. If the make-up of the father = EeFfGg, and the mother = eeFFGg, then find the probability that the child will be:
a. EEFFGG b. eeffgg c. EeFfGg
0 0
d. only the E-trait e. only the e-trait f. all 3 traits
is dominant is recessive recessive
0
g. 3 dominant traits h.only E and G dominant i. only e and g
recessive